Program: 112

When interest compound q times per year at an annual rate of r % for n years, the principal p compounds to an amount a as per the following formula:

a=p(1+r/q)^nq

Write a c program to read 10 sets of p, r, n & q and calculate the corresponding as.

#include<stdio.h>
#include<conio.h>
#include<math.h>
int main()
{
    float p,n,r,q,a;
    int i;
    //for 10 sets we have to create a for loop
    for(i=1;i<=10;i++)
    {
        printf("Set: %d\n",i);
        //accept the values from user
        printf("Enter Principle: ");
        scanf("%f",&p);
        printf("Enter Rate: ");
        scanf("%f",&r);
        printf("Enter Time(in year): ");
        scanf("%f",&n);
        printf("Enter Compound Interest: ");
        scanf("%f",&q);

        //formula
        a = p*(pow((1+r/q),n*q));
        printf("Amount: %.2f\n\n",a);
    }
}

Output:

Set: 1
Enter Principle: 1000
Enter Rate: 10
Enter Time(in year): 1
Enter Compound Interest: 1
Amount: 11000.00

Set: 2
Enter Principle: 2000
Enter Rate: 10
Enter Time(in year): 1
Enter Compound Interest: 1
Amount: 22000.00

Set: 3
Enter Principle: 100
Enter Rate: 1
Enter Time(in year): 1
Enter Compound Interest: 1
Amount: 200.00

Set: 4
Enter Principle: 200
Enter Rate: 5
Enter Time(in year): 1
Enter Compound Interest: 5
Amount: 6400.00

Set: 5
Enter Principle: 622
Enter Rate: 2
Enter Time(in year): 4
Enter Compound Interest: 1
Amount: 50382.00

Set: 6
Enter Principle: 200
Enter Rate: 1
Enter Time(in year): 1
Enter Compound Interest: 10
Amount: 518.75

Set: 7
Enter Principle: 355
Enter Rate: 45
Enter Time(in year): 1
Enter Compound Interest: 21
Amount: 9863834894336.00

Set: 8
Enter Principle: 515
Enter Rate: 5
Enter Time(in year): 1
Enter Compound Interest: 12
Amount: 33652.66

Set: 9
Enter Principle: 110
Enter Rate: 1
Enter Time(in year): 1
Enter Compound Interest: 1
Amount: 220.00

Set: 10
Enter Principle: 200
Enter Rate: 2
Enter Time(in year): 3
Enter Compound Interest: 2
Amount: 12800.00