Program:112
According to a study, the approximate level of intelligence of a person can be calculated using the following formula:
i=2+(y+0.5x)
Write a c program that will produce a table of values of i, y and x, where y varies from 1 to 6, and, for each value of y, x varies from 5.5 to 12.5 in steps of 0.5.
#include<stdio.h> int main() { int y; //y is integer 1 to 6 float i, x; //print column names printf("i\t\ty\tx\n"); //for loop for y range (1 to 6) for(y=1;y<=6;y++) { //for loop for every value y range (5.5 to 12.5 step .5) for(x=5.5;x<=12.5;x=x+0.5) { //formula for intelligence i = 2+(y+0.5*x); //print the values printf("%.2f\t\t%d\t%.2f\n",i,y,x); } } }
Output:
i y x
5.75 1 5.50
6.00 1 6.00
6.25 1 6.50
6.50 1 7.00
6.75 1 7.50
7.00 1 8.00
7.25 1 8.50
7.50 1 9.00
7.75 1 9.50
8.00 1 10.00
8.25 1 10.50
8.50 1 11.00
8.75 1 11.50
9.00 1 12.00
9.25 1 12.50
6.75 2 5.50
7.00 2 6.00
7.25 2 6.50
7.50 2 7.00
7.75 2 7.50
8.00 2 8.00
8.25 2 8.50
8.50 2 9.00
8.75 2 9.50
9.00 2 10.00
9.25 2 10.50
9.50 2 11.00
9.75 2 11.50
10.00 2 12.00
10.25 2 12.50
7.75 3 5.50
8.00 3 6.00
8.25 3 6.50
8.50 3 7.00
8.75 3 7.50
9.00 3 8.00
9.25 3 8.50
9.50 3 9.00
9.75 3 9.50
10.00 3 10.00
10.25 3 10.50
10.50 3 11.00
10.75 3 11.50
11.00 3 12.00
11.25 3 12.50
8.75 4 5.50
9.00 4 6.00
9.25 4 6.50
9.50 4 7.00
9.75 4 7.50
10.00 4 8.00
10.25 4 8.50
10.50 4 9.00
10.75 4 9.50
11.00 4 10.00
11.25 4 10.50
11.50 4 11.00
11.75 4 11.50
12.00 4 12.00
12.25 4 12.50
9.75 5 5.50
10.00 5 6.00
10.25 5 6.50
10.50 5 7.00
10.75 5 7.50
11.00 5 8.00
11.25 5 8.50
11.50 5 9.00
11.75 5 9.50
12.00 5 10.00
12.25 5 10.50
12.50 5 11.00
12.75 5 11.50
13.00 5 12.00
13.25 5 12.50
10.75 6 5.50
11.00 6 6.00
11.25 6 6.50
11.50 6 7.00
11.75 6 7.50
12.00 6 8.00
12.25 6 8.50
12.50 6 9.00
12.75 6 9.50
13.00 6 10.00
13.25 6 10.50
13.50 6 11.00
13.75 6 11.50
14.00 6 12.00
14.25 6 12.50
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